1/2x5+1/5x8+1/8x11+.+1/2006x2009+2009x2013用裂项法计算

来源：学生作业帮编辑：作业帮分类：数学作业时间：2021/04/14 05:48:02

=1/3*(1/2-1/5)+1/3*(1/5-1/8)+.+1/3*(1/2006-1/2009)+1/3*(1/2009-1/2013)
=1/3*(1/2-1/5+1/5-1/8+.+1/2006-1/2009+1/2009-1/2013)
=1/3*(1/2-1/2013)
=1/3*1/2011
=1/6033

2x5/1+5x8/1+8x11/1+.2006x2009/1+2009x2012/1 用裂项法计算 1/2x5+1/5x8+1/8x11+…………+1/2003x2006+1/2006x2009 = 这是我儿子的小学作业裂项法1/2X5+1/5x8+1/8x11.1/2009x2012=? 1/2x5+1/5x8+1/8x11+.+1/32x35 求前n项和1.1/(2X5),1/(5X8),1/(8X11)...2.2＾2/(1X3),4＾2/(3X5),6＾2/ 求数列1/2x5,1/5x8,1/8x11...,1/(3n-1)(3n+2)...的前n项和 2x2/1x3+4x4/3x5+6x6/5x7+8x8/7x9+10x10/9x11+12x12/11x13 仔细看看 1/1x3+1/3x5+1/5x7.1/2009x2010+1/2011x2013 因式分解:X15+X14+X13+X12+X11+X10+X9+X8+X7+X6+X5+X4+X3+X2+X+1 计算：1/1x3+1/3x5+1/5x7+1/7x9+……+1/2011x2013 1/1x3+1/3x5+1/5x7+…+1/2011x2013是多少? 1/(1x3)+1/(3x5)+1/(5x7)+.+1/(2011x2013) 等于什么